200=-16t^2+96t+120

Solution for 200=-16t^2+96t+120 equation:

200=-16t^2+96t+120

We move all terms to the left:

200-(-16t^2+96t+120)=0

We get rid of parentheses

16t^2-96t-120+200=0

We add all the numbers together, and all the variables

16t^2-96t+80=0

a = 16; b = -96; c = +80;
Δ = b2-4ac
Δ = -962-4·16·80
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-64}{2*16}=\frac{32}{32}
=1
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+64}{2*16}=\frac{160}{32}
=5
$